Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Arrange the following ions in order of their increasing size : Li + , Mg 2+ , K + , Al 3+ .
Text Solution
Verified by ExpertsThe correct answer is:
A
Al 3+ < Mg 2+ < Li + < K +
K + has more number of shells than Mg 2+ and AI 3+ . AI 3+ and Mg 2+ are isoelectronic but AI 3+ has higher nuclear charge, so AI 3+ < Mg 2+ . Mg 2+ and Li + have diagonal relationship. But due to +2 charge in Mg 2+ , the Mg 2+ is smaller than Li + . Hence Al 3+ is the smallest one.
K + = 1.38 Å, Li 2+ = 0.76 Å, Mg 2+ = 0.72 Å and Al 3+ = 0.535 Å.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Fill in the blanks : Compounds that formally contain Pb 4+ are easily reduced to Pb 2+ . The stabil…
Among the following, the number of elements showing only one non-zero oxidation state is :
O, Cl, F…
Assertion: F atom has a less negative electron affinity than Cl atom.
Reason: Additional electrons …
Assertion: The first ionization energy of Be is greater than that of B.
Reason: 2p orbital is lower…
The set representing the correct order first ionization potential is
Identify the least stable ion amongst the following: